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Solve the following equations by the elimination method:
x + y = 52x − 3y = 4
y = 3.8, x = 1.2
x = 3.6, y = 1.2
x = 3.8, y = 1.2
x = 3.8, y = 1.22
x + y = 5
Multiplying by 3,∴ 3x + 3y = 15∴ 2x − 3y = 4∴ 5x = 19∴ x = 3.8∴ y = 1.2
The cost of 3 beans and 4 nuts is Rs. 10, and the difference between the price of 2 beans and 2 nuts is Rs. 2. Find the cost of a nut.
Rs. 4
Rs. 3
Rs. 2
Rs. 1
Let the cost of beans be x and that of nuts be y.
3x + 4y = 102x − 2y = 2 …multiplying by 2∴ 4x − 4y = 4... adding with 3x + 4y = 10∴ 7x = 14∴ x = 2, y = 1
In the elimination method, we
substitute one variable in terms of another
eliminate one term by putting a constant
eliminate by making a coefficient of the variable the same
None of these
In the elimination method, we eliminate by making the coefficient of the variable the same.
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